And in those days, it was much more likely that all the code you wrote would be instantly run.
Nothing in the argument required the arc to be a semicircle. If the arc has length xxx times the circumference (where x≤1/2x \leq 1/2x≤1/2), each anchor's event has probability xN−1x^{N-1}xN−1 instead of (1/2)N−1(1/2)^{N-1}(1/2)N−1. Mutual exclusivity still holds because the gap is at least 1−x≥1/21 - x \geq 1/21−x≥1/2 of the circumference, too large for any other anchor's arc to bridge:
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unsigned base-10, 16-bit integer.
第八十三条 有下列行为之一的，处十日以上十五日以下拘留，可以并处五千元以下罚款；情节较轻的，处五日以下拘留或者一千元以下罚款：